E=6c^2−2c−1 F=−4c^2+7c+5 E+F=
1 answer:
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Answer:
The expressions which equivalent to are:
⇒ B
⇒ C
Step-by-step explanation:
Let us revise some rules of exponent
×
=
Now let us find the equivalent expressions of
A.
∵ 4 = 2 × 2
∴ 4 =
∴ =
- By using the second rule above multiply 2 and (n + 2)
∵ 2(n + 2) = 2n + 4
∴ =
B.
∵ 4 = 2 × 2
∴ 4 = 2²
∴ = 2² ×
- By using the first rule rule add the exponents of 2
∵ 2 + n + 1 = n + 3
∴ =
C.
∵ 8 = 2 × 2 × 2
∴ 8 = 2³
∴ = 2³ ×
- By using the first rule rule add the exponents of 2
∵ 3 + n = n + 3
∴ =
D.
∵ 16 = 2 × 2 × 2 × 2
∴ 16 =
∴ =
×
- By using the first rule rule add the exponents of 2
∵ 4 + n = n + 4
∴ =
E.
is in its simplest form
The expressions which equivalent to are:
⇒ B
⇒ C
