Answer:
a) P(X=2)= 0.29
b) P(X<2)= 0.59
c) P(X≤2)= 0.88
d) P(X>2)= 0.12
e) P(X=1 or X=4)= 0.24
f) P(1≤X≤4)= 0.59
Step-by-step explanation:
a) P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4)= 1-0.41-0.18-0.06-0.06= 0.29
b) P(X<2)= P(X=0) + P(X=1)= 0.41 + 0.18 = 0.59
c) P(X≤2)= P(X=0) + P(X=1) + P(X=2)=0.41+0.18+0.29= 0.88
d) P(X>2)=P(X=3) + P(X=4)=0.06+0.06= 0.12
e) P(X=1 or X=4)=P(X=1 ∪ X=4) = P(X=1) + P(X=4)=0.18+0.06= 0.24
f) P(1≤X≤4)=P(X=1) + P(X=2) + P(X=3) + P(X=4)=0.18+0.29+0.06+0.06= 0.59
The probability that none of the four have been vaccinated is
(1-0.63)^4 = 0.01874161
The probability that at least one has been vaccinated is the complement of this,
≈0.9813
Answer:
43.6 (approximately)
Step-by-step explanation:
Diagonal measures of the screen is,
√(35²+26²)
= √(1901)
= 43.6 (approximately)
Answered by GAUTHMATH
Let <span>sin(90° - )------------------------ > sin (90-x)
</span>sin(a - b<span>) = sin a*cos b - cos a*sin b
</span><span>so
</span>sin(90 - x) = sin 90*cos x - cos 90 * sin x
sin(90 - x) = 1*cos x - 0* sin x-------- > cos x
the answer is the option <span>D. cos()</span><span>
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