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Svetllana [295]
3 years ago
15

What's 1/2 of 23 ????????????????????

Mathematics
2 answers:
ivann1987 [24]3 years ago
7 0
Your answer will be:

11.5 is half of 23
max2010maxim [7]3 years ago
5 0
Half of 23 would 11.5 and you had to do was divide 23 by 2


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Help fast will mark you the brainlest
zmey [24]

Answer:

55°

Step-by-step explanation:

x°+35° is a right angle

so x°+35°= 90°

then : x° = 90°-35° = 55°

8 0
3 years ago
Read 2 more answers
On a given day, 36 of the 445 students in a school were absent. What was the appproximate absentee rate that day?
Nata [24]

Answer: The approximate absentee rate that day would be 8.09%.

Step-by-step explanation:

Since we have given that

Number of students who were absent = 36

Total number of  students = 445

We need to find the approximate absentee rate that day :

Rate of absentee of that day would be

\dfrac{\text{Number of absentee}}{\text{Total number of students}}\times 100\\\\=\dfrac{36}{445}\times 100\\\\=8.09\%

Hence, the approximate absentee rate that day would be 8.09%.

5 0
3 years ago
Which of the following are true statements using the Associative Property of Multiplication?
dangina [55]

Answer:

All of the following statements are true because the products, three or four numbers, remain the same regardless of how the numbers are grouped.

3 0
3 years ago
Read 2 more answers
Please help me out with this question
sleet_krkn [62]

Answer:

0.31%

Step-by-step explanation:

Just look at the graph my man

5 0
3 years ago
businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message
KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: \lambda=\frac{62.7}{24}= 2.6125.

The probability of a random variable can be computed using the formula:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

              = 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0
3 years ago
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