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vovikov84 [41]
3 years ago
6

I'm doing some maths homework and need some help. It's Pythagorean

Mathematics
2 answers:
VikaD [51]3 years ago
8 0

Answer:

Step-by-step explanation:

Rainbow [258]3 years ago
6 0
What is the question? Pythagorean is not too hard. a^2 + b^2 = c^2
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Answer:

m<YX=60° is a required answer

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Solve for m: 3m – 4n + 6p &gt; 5n + 2p – 8
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I hope this helps you

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Identify the function in standard form. 2x2 - 4x + 6 = 0 5x2 - 10x + 5 = 0 3x2 + 6x - 12 = 0 3x2 + 2x + 10 = 0
MrRa [10]

Answer:

Standard form of a quadratic equation is;  

ax^2+bx+c=0  

According to the above equations, all of them are in standard form.

Step-by-step explanation:

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{25 OR 50 POINTS} Solve for X: -2+3x=46<br><br> A) -5<br> B) -2<br> C) -16<br> D) 16
Jobisdone [24]

Answer:

D) 16

Step-by-step explanation:

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3 years ago
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Please show me step by step how to do this
Stels [109]

Answer:

The next three terms of the sequence are 17, 21 and 25.

The 300th term of the sequence is 1197.

Step-by-step explanation:

The statement describes an arithmetic progression, which is defined by following formula:

p(n) = p_{1}+r\cdot (n-1) (1)

Where:

p_{1} - First element of the sequence.

r - Progression rate.

n - Index of the n-th element of the sequence.

p(n) - n-th element of the series.

If we know that p_{1} = 1, n = 2 and p(n) = 5, then the progression rate is:

r = \frac{p(n)-p_{1}}{n-1}

r = 4

The set of elements of the series are described by p(n) = 1 + 4\cdot (n-1).

Lastly, if we know that n = 300, then the 300th term of the sequence is:

p(n) = 1 + 4\cdot (n-1)

p(n) = 1197

And the next three terms of the sequence are:

n = 5

p(n) = 1 + 4\cdot (n-1)

p(n) = 17

n = 6

p(n) = 1 + 4\cdot (n-1)

p(n) = 21

n = 7

p(n) = 1 + 4\cdot (n-1)

p(n) = 25

The next three terms of the sequence are 17, 21 and 25.

The 300th term of the sequence is 1197.

8 0
3 years ago
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