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pashok25 [27]
3 years ago
13

How do you simplify this expression

Mathematics
1 answer:
raketka [301]3 years ago
3 0
Convert <span>6\frac{3}{8}<span>6<span><span>​8</span>​<span>​3</span><span>​​</span></span></span></span><span> to improper fraction. Use this rule: </span><span>a \frac{b}{c}=\frac{ac+b}{c}<span>a<span><span>​c</span>​<span>​b</span><span>​​</span></span>=<span><span>​c</span>​<span>​<span>ac+b</span></span>​​:</span></span></span>
​∣8<span><span>​<span>​<span>6×8+3</span></span><span>​​</span></span>−2∣+∣−8<span><span>​8</span>​<span>​5</span><span>​​</span></span>−1<span>∣


</span></span>Simplify <span>6\times 8<span>6×8</span></span><span> to </span>48: <span><span><span><span><span>
​</span>8</span>​<span>​<span>48+3</span></span><span>​​</span></span>−2∣+∣−8<span><span>​8</span>​<span>​5</span><span>​​</span></span>−1∣


</span>Simplify <span>48+3<span>48+3</span></span><span> to </span>51:</span><span><span><span><span><span>
​</span>8</span>​<span>​<span>51</span></span><span>​​</span></span>−2∣+∣−8<span><span>​8</span>​<span>​5</span><span>​​</span></span>−1∣

</span> Make the denominators the same:
<span><span><span>51</span><span>​​/8</span></span>−2×<span><span>​8</span>​<span>​8</span><span>​​

</span></span></span><span>Simplify. Denominators are now the same:
</span>
<span><span><span>51</span><span>​​/8</span></span>−<span><span>​8</span>​<span>​<span>16</span></span><span>​​
</span>
</span></span>Join the denominators: \frac{51-16}{8}<span><span>​8</span>​<span>​<span>51−16</span></span><span>​​
</span>
etc.. and your answer will be 14

</span></span>
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Marrrta [24]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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How can you get the variable alone in the<br> equation 25?<br> 5<br> a
WARRIOR [948]

Answer:

5

Step-by-step explanation:

5x5=25

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Factor the trinomial. Factor out the GCF first.<br> 5x^2y - 30xy^2 - 35y^3
anzhelika [568]

Answer: 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

Step-by-step explanation:

GCF = Greatest common factor.

For example: 6 is the GCF of 12 and 18.

The given expression: 5x^2y - 30xy^2 - 35y^3

It can be written as

5x^2y - (5\times6)x( y\times y) - (5\times7)(y^2\times y)

Taking out common factor  5y , we get

5y(x^2-6xy-7y^2)\\\\ =5y(x^2+xy-7xy-7y^2)\  \ [\because-6xy=xy-7xy]\\\\=5y(x(x+y)-7y(x+y))\\\\= 5y((x+y)(x-7y))\\\\=5y(x+y)(x-7y)

Hence, 5x^2y - 30xy^2 - 35y^3=5y(x+y)(x-7y)

3 0
3 years ago
Please Help!
Bingel [31]
The tank is NOT filled with 8314.5 L of a liquid. I guess you meant <span>The tank is completely filled with 8314.5 grams of liquid." </span>
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3 0
3 years ago
Please see the image and help with this homework problem. thank you!
dimulka [17.4K]

we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

For t=28

\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>
6 0
1 year ago
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