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To be able to determine the type of skew exhibited by the distribution of the heights he achieved in each of his attempt we arrange the distribution in order and obtain the frequency of each data in the distribution. Height (meters): 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24 Frequency: 2, 1, 1, 2, 2, 3, 1, 2, 1, 1, 1, 1, 1, 1 Calculating the mean gives (11 x 2 + 12 + 13 + 14 x 2 + 15 x 2 + 16 x 3 + 17 + 18 x 2 + 19 + 20 + 21 + 22 + 23 + 24) / 20 = 335 / 20 = 16.75 Since there are more higher frequencies to the left of the mean we conclude that the distribution exhibits a positive skew.
Answer:
3 3/6 or 3 1/2 or 3.5
Step-by-step explanation:
Answer: B
Step-by-step explanation:
Hello :
<span>note :
an equation of the
circle Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : </span><span>x²+y²-16x+6y+53=0
(</span>x²-16x) +( y²+6y ) +53 = 0
(x² -2(8)x +8² - 8²) +(y² +2(3)x -3²+3² ) +53=0
(x² -2(8)x +8²) - 8² +(y² +2(3)x +3²)-3² +53=0
(x-8)² +( y+3)² = 20
the center is : w(8,-3) and ridus : r = <span>√20</span>
