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Dennis_Churaev [7]
3 years ago
10

Coffee is sold in jars

Mathematics
2 answers:
Neko [114]3 years ago
6 0

Answer:

a. 448g

b. About 3 jars. (2.24 to be precise :) )

c. 560g

d. He still needs to buy 3 jars becuase 560 is less than 600, the product of 200 x 3j (j=jars), and 560/200 = 2.8, also less than 3.

Step-by-step explanation:

a. 2 x 8 = 16(grams), 16 x 28 =448.

b. 448/200 equals 2.24, 2.24 is a higher number than 2(jars), so he woukd have to buy 3 to cover the other 0.24.

c. 2.5 x 8 = 20, 20 x 28 = 560.

d. (self explanitory)

MissTica3 years ago
5 0

Answer:

3

Step-by-step explanation:

8 x 2g= ibg per day

28 days  - 16 x 28  = 448g

2 jars = 400 g

soo he would need to buy 3

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Answer:

The area of a shape is the amount of space it occupies

Step 1:

We start by calculating the area of the rectangle using:

\begin{gathered} A_{rectangle}=l\times b \\  \end{gathered}

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\begin{gathered} A_{rectangle}=l\times b \\ A_{rectangle}=20cm\times5cm \\ A_{rectangle}=100cm^2 \\ A_1=100cm^2 \end{gathered}

Step 2:

we calculate the area of the triangle using:

A_{triangle}=\frac{1}{2}\times base\times height

By substituting the values, we will have

\begin{gathered} A_{tr\imaginaryI angle}=\frac{1}{2}\times base\times he\imaginaryI ght \\ A_{tr\mathrm{i}angle}=\frac{1}{2}\times10cm\times8cm \\ A_{tr\mathrm{i}angle}=\frac{80cm^2}{2} \\ A_{tr\mathrm{i}angle}=40cm^2 \\ A_2=40cm^2 \end{gathered}

Step 3:

Calculate the area of the two semicircles

A_{semicircle}=\frac{\pi r^2}{2}

By substituting the values, we will have

\begin{gathered} A_{sem\imaginaryI c\imaginaryI rcle}=\frac{\pi r^{2}}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=3.14\times\frac{5^2}{2} \\ A_{sem\mathrm{i}c\mathrm{i}rcle}=39.25cm^2 \\ Area\text{ of two semicircle will be} \\ A_3=39.25cm^2\times2 \\ A_3=78.5cm^2 \end{gathered}

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A_{shape}=A_1+A_2+A_3

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\begin{gathered} A_{shape}=A_{1}+A_{2}+A_{3} \\ A_{shape}=100cm^2+40cm^2+78.5cm^2 \\ A_{shape}=218.5cm^3 \end{gathered}

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1 year ago
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Answer:

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