From least to greatest. in this order 115/11 10.5624 115
Since the radicands (the number under the radical) are the same, add the coefficients and keep the radicand.
4√5 + 2√5 = 6√5
LETTER C
Answer:
9,11
Step-by-step explanation:
let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)
therefore;
x(x+2)= 99
x²+2x=99
I usually solve the sum like this,
we need to find the nearest square number ( number smaller than the number on the R.H.S)
here, it is 81, whose square root is 9. therefore the solution is 9
verification:
(9)²+2*9=99
81+18=99
99=99
hence, 9 is the solution. therefore the positive odd consecutive integers are
x=9
x+2=9+2= 11
verification:
9*11=99
99=99
L.H.S=R.H.S
Answer:
The answer is 0.749 L.
Step-by-step explanation:
L, dc, cl, ml
0. 7 4 9
