It is stil half becuase the real probability doesnt change
For this case what we have to take into account is the following variable:
x = represent the unknown number
We now write the following inequality:
"four times the sum of number and 15 is at least 20"
4 (x + 15)> = 20
We clear the value of x:
(x + 15)> = 20/4
(x + 15)> = 5
x> = 5 - 15
x> = - 10
The solution set is:
[-10, inf)
Answer:
all possible values for X are:
[-10, inf)
Answer:
absolute vlaue inequality: |x-3| > 9; solved: x<-6 and x>12
Step-by-step explanation:
I’m going to start this off by saying I learned all this right now by just searching up how to solve an absolute inequality equation and watching one video, so this might not be an accurate explanation. (I’m pretty sure the answer’s right though)
So an absolute value inequality must be written like this:
| x - a | *inequality* b
a is going to be the number that the inequality is centered around, in this case, 3. b will be how far you can deviate from that number, which in this case is 9.
Now, you will have this:
|x - 3| *inequality* 9
Now, to find the inequality, you need to understand the wording. If it says “more than” as it does here, then you would have the greater-than symbol (>). If you have “less than” then you’d have the less-than symbol (<). If the problem says “at least b away” then it would be greater-than-or-equal to (≥), and likewise, if it says “at most b away” then it would be less-than-or-equal-to (≤).
So now we're at:
|x - 3| > 9
To solve the equation, you just need to subtract 9(b) from 3(a) and add 9(a) to 3(b) to get -6 and 12. Since x must be more than 9 units away, you would get:
x<-6 and x>12
Hope this is helpful!
1. B
2. A
3. D
4. D
I'm not too sure about 1 but I'm sure about the others. Hope this helps!
Answer:
see explanation
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
J (1, 4 ) → J' (- 1, 4 )
K (1, 0 ) → K' (- 1, 0 )
L (4, 3 ) → L' (- 4, 3 )
Plot the points J', K', L' and connect them in order to obtain image
