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choli [55]
3 years ago
14

there was a giant brownie on a plate at a birthday party ben ate 5/12 of the brownie walter ate 2/5 of the brownie how much more

of the brownie did ben eat
Mathematics
1 answer:
harkovskaia [24]3 years ago
3 0
Ben ate 1/60more than Walter
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Write an equation in slope-intercept form of the line that passes through (6, -1) and (3, 47)
katrin2010 [14]

Answer:

Step-by-step explanation:

(47+1)/(3-6) = 48/-3 = -16

y + 1 = -16(x - 6)

y + 1 = -16x + 96

y = -16x + 95

6 0
3 years ago
Write the ratio as<br> fraction in simplest form, with<br> 16 gal to 72 gal
V125BC [204]

Answer:

2/9

Step-by-step explanation:

16/72 simplify in calculator =2/9

5 0
2 years ago
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Kenya dose the pole vault for her school's track team. Her record is 2 meters 86 centimetres. How many millimetres is Kenya's re
kvv77 [185]

Answer:

2860

Step-by-step explanation:

First, convert 2 meters into cm and then convert to mm. m to cm+200cm cm-mm= 2000. Then turn 86 centimetres into mm which is 860 mm. Lastly 2000+860=2860. Hope this helps

6 0
1 year ago
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Which set of ordered pairs and equation for a best fit line represents data from the table?. a. (x1, y1) = (64, 135), (x2, y2) =
Marrrta [24]
Just comparing your (x, y) points to the values on the table, it looks like b) would be the quick answer. Since it states under the table to use average values within each range.
So for x=62 (the weight), we have y=122 (the iron count) which would be the average of the range between 115 and 129.

Similiarly, x=70 corresponds to y=146, which is the average of 139 and 153.
You could take the average values of your highest and lowest iron count ranges compare them to the max-min weight to get your slope. Looks like it would be (155-112)/(73-58)= 43/15= 2.8666 repeating. That would make sense with the slope in the equation listed in b) as well. <span>
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8 0
3 years ago
7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

  x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0
2 years ago
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