Answer: 12
Step-by-step explanation:
Given the question :
Given the four digits 2, 4, 6, and 7, how many different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer?
The number of different positive two integer number can be obtained by:
P(4, 2) = 4P2
Recall:
nPr = n! / (n - r)!
4P2 = 4! / (4 - 2)!
4P2 = 4! / 2!
4P2 = (4 * 3 * 2 * 1) / ( 2 * 1)
4P2 = 24 / 2
4P2 = 12
Hence, 12 different positive two-digit integers can be formed using these digits if a digit may not be repeated in an integer
Hello there! the winning time is 59.625 seconds.
This is the person who completed the lowest amount of time, meaning they finished first. The others too longer so they finished later, meaning they didn't win.
I hope this was helpful and have a great day! :)
Let a be the <span>other leg.
</span>
By the Pythagorean theorem:
Answer:
Third option
Step-by-step explanation:
: ) Hope u will have a great day
