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aliya0001 [1]
3 years ago
14

I tried many times to solve this question: Joy makes 6,5 litres soup correct to the nearest 0.5 litres. She serves the soup in 2

80ml portions correct to the nearest 10ml. 22 people order this soup. Does joy definitely has enough soup to serve the 22 people. show how you decide Your final line must be written as joy definitely does have enough soup or joy may not have enough soup. If you can please explain it if not just give the answer.
Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

Joy makes 6.5 litres soup correct to the nearest 0.5 litres. She serves the soup in 280ml portions correct to the nearest 10ml. 22 people order this soup. Does joy definitely has enough soup to serve the 22 people.

Answer:

Yes, Joy definitely does has enough soup

Step-by-step explanation:

From the question, we know,

Joy make 6.5 litres of soup

Serves it in 280ml portions

Step 1

We convert the portions to liters

1 ml = 0.001 litre

280 ml

= 280ml × 0.001 litre/1 ml

= 0.28litre

Step 2

We divide 6.5 liters by 0.28 to find out how many people can be served

= 6.5 ÷ 0.28

= 23.2142857143 people

We can see that 6.5 liters soup can serve 23 people approximately.

Therefore, Yes, Joy definitely does has enough soup to serve 22 people

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Mnenie [13.5K]

Answer:

Expected number of sweaters per month can be given as follows:

E(X) = Σ x P(X = x)

Now,

E(X) = [2 * 0.1 + 3* 0.1+ 4* 0.2 + 5* 0.3 + 6* 0.2 + 7 * 0.1]

E(X) = 4.7.

Var(X) = E(X^2) – [E(X)]^2

     We have E(X) = 4.7. Thus, [E(X)]2= 4.7*4.7 = 22.09.

Now E(X^2) = [2*2 * 0.1 + 3*3* 0.1+ 4*4* 0.2 + 5*5* 0.3 + 6*6* 0.2 + 7*7*0.1]

    E(X^2) = 24.1

Thus by formula, Var(X) = E(X2) – [E(X)]2

Var(X) = 24.1-22.09

Var(X) = 2.01

Given that exporter pays the $12 for each sweater. The woman pays $2 per sweater. The cost of shipment is $3 irrespective of the number of sweaters. Now, let m is the number of sweaters she made. Thus, the total cost she would have to pay would be

Total cost by woman = 2m+3

The total cost paid by the exporter would be = 12m.

Now the profit of woman would be given by,

                  = The total cost exporter pay – cost paid by the woman

                 = 12m – (2m +3)

                 = 12m – 2m -3

                 = 10m – 3.

Now expected profit made by the woman is given in the following table below:

E(Profit) = Σ profit* P(X = x)

In a similar way, as we have done in part (a).

E(Profit) = [17 * 0.1 + 27* 0.1+ 37* 0.2 + 47* 0.3 + 57* 0.2 + 67 * 0.1]

E(Profit) = 44.

Now, we calculate the variance:

Var(profit) = E(profit^2) – [E(profit)]^2

Var(profit) =

E(profit^2) = [17*17 * 0.1 + 27*27* 0.1+ 37*37* 0.2 + 47*47* 0.3 + 57*57* 0.2 + 67*67*0.1]

    E(profit^2) = 2137.

[E(profit)]^2 = 44*44 = 1936.

Thus, the variance can be given as =

Var(profit)= 2137 – 1936

Var(profit) = 201.

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Answer:

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