Answer:
f(-14) = -6
f(-4) = 6
f(12) = 6
f(0) = -3
negative
Step-by-step explanation:
f(-14) = -6
This is because when x is -14, y is -6, as seen in the graph
f(-4) = 6
This is because when x is -4, y is 6, as seen in the graph
f(12) = 6
This is because when x is 12, y is 6, as seen in the graph
f(0) = -3
This is because when x is 0, y is -3, as seen in the graph
is f(4) positive or negative?
negative
This is because when x is 4, y is -6, as seen in the graph
Answer:
a)Null hypothesis:
Alternative hypothesis:
b) A Type of error I is reject the hypothesis that 
is equal to 40 when is fact ![\mu is equal to 40c) We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"Step-by-step explanation:Assuming this problem: "Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, [tex]\mu](https://tex.z-dn.net/?f=%5Cmu%20is%20%3Cstrong%3Eequal%20to%2040%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3Ec%29%20We%20can%20commit%20a%20Type%20II%20Error%2C%20since%20by%20definition%20%22A%20type%20II%20error%20is%20the%20non-rejection%20of%20a%20false%20null%20hypothesis%20and%20is%20known%20as%20%22false%20negative%22%20conclusion%22%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAssuming%20this%20problem%3A%3C%2Fstrong%3E%20%22Some%20college%20graduates%20employed%20full-time%20work%20more%20than%2040%20hours%20per%20week%2C%20and%20some%20work%20fewer%20than%2040%20hours%20per%20week.%20We%20suspect%20that%20the%20mean%20number%20of%20hours%20worked%20per%20week%20by%20college%20graduates%2C%20%5Btex%5D%5Cmu)
, is different from 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 43 hours and that the standard deviation is 4 hours. Based on this information, answer the questions below"
Data given
represent the sample mean
population mean (variable of interest)
s=4 represent the sample standard deviation
n represent the sample size
Part a: System of hypothesis
We need to conduct a hypothesis in order to determine if actual mean is different from 40 , the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Part b
In th context of this tes, what is a Type I error?
A Type of error I is reject the hypothesis that is equal to 40 when is fact [tex]\mu is equal to 40
Part c
Suppose that we decide not to reject the null hypothesis. What sort of error might we be making.
We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"
Answer:
as in pic below
Step-by-step explanation:
3x + y = 3
7x + 2y = 1
First isolate one of the variables (x or y) in one of the equations.
Isolate "y" in the first equation(because it is the easiest to isolate) and substitute it into the second equation.
3x + y = 3 Subtract 3x on both sides
3x - 3x + y = 3 - 3x
y = 3 - 3x
7x + 2y = 1
7x + 2(3 - 3x) = 1 [since y = 3 - 3x, you can substitute (3-3x) for "y"]
Multiply/distribute 2 into (3 - 3x)
7x + (3(2) - 3x(2)) = 1
7x + 6 - 6x = 1
x + 6 = 1 Subtract 6 on both sides
x = -5
Now that you know "x", substitute it into one of the equations (I will do both)
3x + y = 3
3(-5) + y = 3 [since x = -5, you can plug in -5 for "x"]
-15 + y = 3 Add 15 on both sides
y = 18
7x + 2y = 1
7(-5) + 2y = 1
-35 + 2y = 1 Add 35 on both sides
2y = 36 Divide 2 on both sides
y = 18
x = -5, y = 18 or (-5, 18)
Not sure what the question is
But 1/4 as a decimal gives us 0.25
