Which equation has the steepest graph
1 answer:
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The volume for any cylinder, right or oblique, would be base x height. Even though an oblique cylinder looks quite different from a right cylinder, their volumes would be equal (given that their radius and height are equal). Think about it, the area of a parallelogram would equal the area of the rectangle if their heights and bases were the same, so that would apply for this also.
V= Bh
The base would stand for that top and bottom of the cylinder, or the circles. The volume for circle is pi x radius squared.
V =
h
V =
256 x 16
V =4096 
V= Bh
The base would stand for that top and bottom of the cylinder, or the circles. The volume for circle is pi x radius squared.
V =
V =
V =
Answer:
(1) D.Angle C is congruent to to Angle F. (2) C. SSS. (3) C. cannot be congruent to.
Step-by-step explanation:
1)
From the given figure it is noticed that
According to SAS postulate, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then both triangles are congruent.
The included angles of congruent sides are angle C and angle G.
So, condition "Angle C is congruent to to Angle F" will prove that the ∆ABC and ∆EFG are congruent by the SAS criterion.
2)
If
According to SSS postulate, if all three sides in one triangle are congruent to the corresponding sides in the other.
Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore SSS criterion for congruence is violated.
3)
Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore the included angle of congruent sides are different.
Therefore angle C and angle F cannot be congruent to each other.