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borishaifa [10]
3 years ago
6

2x + 5 = 3x + 7 please help

Mathematics
2 answers:
Yakvenalex [24]3 years ago
6 0
2x+5=3x+7

Move all the x's to one side of the equation. Subtract both sides by 3x

2x+5-3x=3x+7-3x
-x+5=7

Subtract both sides by 5 to eliminate the "5" on the left side

-x+5-5=7-5
-x=2

Multiple/divide (doesn't matter) both sides by -1

x=-2

That's the solution. Hope this helps! :)
Sever21 [200]3 years ago
5 0
Explanation: 
When we have variables on both sides we look for the coefficient that is lower than the two and reverse the sign.  


Example: 

1x+ 4 = 2x+3 

We reverse 1x sign because it is lower so we will be subtracting

2x-1x = 1x

1x+3=4 

We would then solve for x.


-

Let's begin to solve. 

Step 1:
You would look for the coefficient or variable that is less and reverse the sign. 
In this question the lower number is -x and so we would reverse the sign to add. 
3x-2x= 1x


Step 2: 
We now have
1x+7=5


Step 3: 
We will subtract 7 from to find X5 -7 = -2


Step 4:
1x = -2
Divide both sides by one to find x 


Our answer:
\boxed{x=-2}


-

Summary:
We first looked for the lower coefficient (in this case variable). We then flipped the sign and solved for x. 

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Klio2033 [76]

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3 years ago
The circle below is centered at the origin and has a radius of 7. What is its
Rashid [163]

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x² + y² = 49

Step-by-step explanation:

The equation for a circle is: x² + y² = r²

here, we know our circle's radius (r) to be 7

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hope this helps!! have a lovely day :)

7 0
2 years ago
An athletic field is a 60 yd60 yd​-by-120 yd120 yd ​rectangle, with a semicircle at each of the short sides. A running track 101
gregori [183]

Distance of each track are:

D₁ = 428.5 yd

D₂ = 436.35 yd

D₃ = 444.20 yd

D₄ = 452.05 yd

D₅ = 459.91 yd

D₆ = 467.76 yd

D₇ = 475.61 yd

D₈ = 483.47 yd

<u>Explanation:</u>

Given:

Track is divided into 8 lanes.

The length around each track is the two lengths of the rectangle plus the two lengths of the semi-circle with varying diameters.

Thus,

D = 2(120) + 2. \frac{1}{2} \pi d\\\\D = 240 + \pi d

Starting from the innermost edge with a diameter of 60yd.

Each lane is 10/8 = 1.25yd

So, the diameter increases by 2(1.25) = 2.5 yd each lane going outward.

So, the distances are:

D₁ = 240 + π (60) → 428.5yd

D₂ = 240 + π(60 + 2.5) → 436.35 yd

D₃ = 240 + π(60 + 5) → 444.20 yd

D₄ = 240 + π(60 + 7.5) → 452.05 yd

D₅ = 240 + π(60 + 10) → 459.91 yd

D₆ = 24 + π(60 + 12.5) → 467.76 yd

D₇ = 240 + π(60 + 15) → 475.61 yd

D₈ = 240 + π(60 + 17.5) → 483.47 yd

4 0
3 years ago
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