Find the product. (-5a2)3 · a5

Mathematics

1 answer:

MakcuM [25]4 years ago

8 0

Answer:

-125a^30

Step-by-step explanation:

(-5a^2)^3 · a^5

-5³ a^(2×3) a^5

-125 a^(6×5)

-125a^30

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Using Newton's Law of Cooling. You are a medical examiner called to an abandoned house in which a dead body has been discovered.

Artyom0805 [142]

A) The differential equation comes from the fact that the rate of temperature change is proportional to the difference in temperatures.
$\frac{dT}{dt} = \alpha(T -52)$

B) Find general solution by separating variables and integrating $\int\frac{dT}{T-52} = \alpha \int dt \\ ln (T-52) = \alpha t + C \\ T = C e^{\alpha t} +52$ :

C) Initial condition is t=0, T = 87
$87 = C +52 \\ C = 35$

D) Total time elapsed is 10 minutes, new temperature is 84
$84 = 35 e^{10\alpha} +52$
solve for alpha
$e^{10\alpha} =\frac{32}{35} \\ \alpha = \frac{ln(32/35)}{10} \\ \alpha = -.00896$

E) Temperature function is:
$T = 35 e^{-.00896 t} +52$
solving for t
$t = \frac{ln (\frac{T-52}{35})}{-.00896}$
Plug in T = 98.6
$t = -31.95$

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3 years ago

E=mc square m=3 c=6 solve for E

just olya [345]

Answer:

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E = 3(36)

E = 108

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3 years ago

Y=[[x]]<br> evaluate this function at x=3

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