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lisabon 2012 [21]
2 years ago
14

What is the species name for humans​

Biology
2 answers:
Stolb23 [73]2 years ago
7 0

Answer: Homo sapiens

Scorpion4ik [409]2 years ago
5 0

Answer: Sapiens

Explanation:

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What is the value of the expression 3 divided by 3/4
Leto [7]

Answer:

4

Explanation:

If we have the expression, 3/3/4.

Then this is the same as 3 × 4/3

Which is the same as 12/3

Which is the same as 4

Hence the value of the expression 3/3/4 is 4

5 0
3 years ago
Sonya is studying a nonmetal element. She learns that the element is like other elements in its group because it can bond to for
NemiM [27]

Answer:

The answer is C) fluorine (F)

6 0
3 years ago
Read 2 more answers
The elephants represented in lanes 3 and 5 could have been a match to the ivory sample if you failed to amplify one allele in ei
olga_2 [115]

About the question:

I failed to find the result of the PCR / electrophoresis. However, I will try to explain when to still consider a sample, and when to exclude it.

Answer:

Probably elephants 1, 2, 4, and 6 exposed a pattern of lines that differed in most alleles from the ivory´s pattern. So they were considered to be different and, hence, excluded. However, elephants 3 and 5 only were different in one allele, which might be due to the amplification failure. In these last situations, the experiment must be run again, and include many markers.

Explanation:

The genetic profile is the series of alleles, characteristic of each individual, concerning a series of DNA fragments.

Once genetic profiles are obtained by using PCR/electrophoresis, they must be subjected to interpretation. The researcher must compare profiles to find concordance between individuals or the lack of it.

In the exposed example, probably we have a profile of the ivory sample, and we need to find out to what individual or population it belongs to. So we need to compare the pattern of bands of the different lanes with the ivory´s pattern of bands.

In resumed terms, if the ivory´s patterns completely match with another lane pattern, then this is the individuals or population to whom it belongs the ivory. However, if they do not match, we need to exclude this individual.

But this is not as easy as it looks like. Sometimes it is difficult to interpret the results because bands are not so clear, and sometimes there are failures during amplification, as said before in the statement of the problem.

In these situations, what you need to do is look for the lanes that match the most with the ivory one and discard those that differ the most. These last patterns probably belong to a different animal or population, that why they can be excluded. Individuals suspected of being the same as the individual understudy or belonging to the same population, must be subducted to a repetition of the study. Also, the use of several markers in the study increases the matches chances.

So, in the exposed example, if the amplification fails in one allele, elephants 3 and 5 could be a match to the ivory sample, probably because all the other alleles do match. You can only exclude them if, after the experiment repetition, the involved allele is still different. On the other hand, you can eliminate the elephants 1, 2, 4, and 6 because their pattern bands are significantly different from the ivory´s patterns, so you do not even need to repeat the experiment.

7 0
2 years ago
In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

4 0
2 years ago
What role does cellular respiration play in the carbon cycle?
Maru [420]

Cellular respiration and photosynthesis are important parts of the carbon cycle. The carbon cycle is the pathways through which carbon is recycled in the biosphere. While cellular respiration releases carbon dioxide into the environment, photosynthesis pulls carbon dioxide out of the atmosphere. The exchange of carbon dioxide and oxygen during photosynthesis (Figure below) and cellular respiration worldwide helps to keep atmospheric oxygen and carbon dioxide at stable levels.


6 0
3 years ago
Read 2 more answers
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