Answer:
0.6
Step-by-step explanation:
In the question, we are told that:
The probability that John gets a B is 0.3 .
The probability that Mary gets a B is 0.4 .
The probability that neither gets an A but at least one gets a B is 0.1
The probability that at least one gets a B but neither gets a C
=( The probability that John gets a B ) +( The probability that Mary gets a B )- (The probability that neither gets an A but at least one gets a B is 0.1
= 0.3 + 0.4 - 0.1
= 0.7 - 0.1
= 0.6
Therefore, the probability that at least one gets a B but neither gets a C is 0.6
