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Scilla [17]
4 years ago
13

Two samples were taken at a shopping mall. In each sample, 200 shoppers were asked which fruit they preferred.

Mathematics
2 answers:
AfilCa [17]4 years ago
6 0

Answer:

the answer is C

Step-by-step explanation:

About the same number of people prefer apples and bananas.

GenaCL600 [577]4 years ago
3 0

Answer: about The same number of people prefer apples or bananas

Step-by-step explanation:

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Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
Rzqust [24]

Answer:

a = 6 or 9

Step-by-step explanation:

The "a", "b", and "c" of the quadratic formula are the coefficients of a², a, and the constant term in the given equation:

... a = 2, b = -30, c = 108

Then the quadratic formula tells you the solutions are ...

... (-b ± √(b² -4ac))/(2a)

... = (-(-30) ± √((-30)² -4(2)(108)))/(2(2))

... = (30 ± √(900 -864))/4

... = (30 ± √36)/4

... = (30 ± 6)/4 = {24, 36}/4

... = {6, 9}

_____

The <em>a</em> variable should not be confused with the "a" that is used to name the coefficient of the square of the variable in the quadratic formula. If it is too confusing, rewrite one or the other. For example, you could write ...

... The solution to pa² +qa +r = 0 is ... a = (-q ± √(q²-4pr))/(2p)

where p=2, q=-30, r=108 in the given equation.

5 0
3 years ago
A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi
SVETLANKA909090 [29]

Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

= \frac{20!}{(20-5)! 5!)}

= \frac{20*19*18*17*16}{5*4*3*2*1}

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

= \frac{20}{320} = \frac{1}{19}

P(A5) = ⁸C₅ / ²⁰C₅

= \frac{56}{15540} = \frac{7}{1938}

P(A4) = ⁷C₄ / ²⁰C₄

= \frac{35}{4845} = \frac{7}{969}

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

5 0
3 years ago
Solve<br> -1/3a+5/6+2 1/6-5/6a
Hunter-Best [27]

Answer:

\frac{-1}{3}a + \frac{5}{6} +2\frac{1}{6} -\frac{5}{6}a\\\\\frac{-1}{3}a + \frac{5}{6} +\frac{13}{6} -\frac{5}{6}a\\\\\frac{-2a + 5 + 13-5a}{6}\\\\\frac{-7a +18}{6}

3 0
3 years ago
Suppose a normal distribution has a mean of 50 and a standard deviation of
hoa [83]

Answer:

27.8% I think

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
V2 + 2v + 1 is the product of which two binomials?
juin [17]
(V+1)2 is that right
6 0
3 years ago
Read 2 more answers
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