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DochEvi [55]
3 years ago
14

A spinner is divided into 8 equal sections, and each section contains a number from 1 to 8. What is the probability of the spinn

er landing on 5?
StartFraction 1 over 13 EndFraction
StartFraction 1 over 8 EndFraction
StartFraction 5 over 13 EndFraction
StartFraction 5 over 8 EndFraction
Mathematics
1 answer:
Elodia [21]3 years ago
8 0

Answer:

StartFraction 1 over 8 EndFraction

Step-by-step explanation:

It would be 1/8 because there is 8 sections on the spinner and 5 is on 1 section of the spinner so it would 1/8.

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Write an equation in slope intercept form given the following slope and point M=-3 (6,-9)​
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Answer:

y = -3x + -9/6

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5 0
2 years ago
What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?
Akimi4 [234]
\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------

\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5
4 0
3 years ago
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Answer:

The photo above show you how to graph it.

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Step-by-step explanation:

Hope this helped

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Answer:

The average speed of the plain was 800 miles/h

Step-by-step explanation:

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