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DochEvi [55]
3 years ago
14

A spinner is divided into 8 equal sections, and each section contains a number from 1 to 8. What is the probability of the spinn

er landing on 5?
StartFraction 1 over 13 EndFraction
StartFraction 1 over 8 EndFraction
StartFraction 5 over 13 EndFraction
StartFraction 5 over 8 EndFraction
Mathematics
1 answer:
Elodia [21]3 years ago
8 0

Answer:

StartFraction 1 over 8 EndFraction

Step-by-step explanation:

It would be 1/8 because there is 8 sections on the spinner and 5 is on 1 section of the spinner so it would 1/8.

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② The complement of an<br> angle. is 10 more<br> than 3 times the<br> angle. Find both
Mrac [35]
Let x be the angle. The complement is 3x + 10. The sum of two complementary angles is 90. So,
x + 3x + 10 = 90
4x + 10 = 90
4x = 80
x = 20
Plug x into the complement
3(20) + 10 = 70

The angle is 20 degrees and the complement is 70 degrees

4 0
3 years ago
Please and thank you
algol [13]

Answer:

the last one

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
N ∆ABC, if sin A = and tan A = , then what is cos A?
leva [86]

Answer:hello :

tanA = sinA/cosA

cosA = sinA /tanA

cosA =(4/5)/(4/3)

cosA=3/5

Step-by-step explanation:

8 0
3 years ago
Y=x+2<br> and then you have x=-3 <br><br><br> You also have to use transitive property
tresset_1 [31]
If y = x+2 and x = -3 then we can say that y = -3+2 after replacing the 'x' with -3

From here, we just add -3 and 2 to get -1 which is why y = -3+2 turns into y = -1

So together x = -3 and y = -1

They pair up to form (x,y) = (-3,-1)
8 0
3 years ago
Those are the math questions I need the answers of ​
Elena L [17]

Answer:

1)

12\sqrt{18}-3\sqrt{50}+\sqrt{32}

12\sqrt{9}\sqrt{2}-3\sqrt{25}   \sqrt{2} +\sqrt{16} \sqrt{2}

12\times3\sqrt{2} -3\times5\sqrt{2}+4\sqrt{2}

36\sqrt{2}-15\sqrt{2}+4\sqrt{2}

25\sqrt{2}

2)

\frac{1}{5+2\sqrt{6}}

Multiply 5-2\sqrt{6}:

\frac{1\times \left(5-2\sqrt{6}\right)}{\left(5+2\sqrt{6}\right)\left(5-2\sqrt{6}\right)}

Apply Difference of Squares formula: (a+b)(a-b)=a^2-b^2

\frac{5-2\sqrt{6}}{5^2-\left(2\sqrt{6}\right)^2}

\frac{5-2\sqrt{6}}{25-2^2\left(\sqrt{6}\right)^2}

\frac{5-2\sqrt{6}}{25-4\times6}

\frac{5-2\sqrt{6}}{1}

{5-2\sqrt{6}}

a = 5, b = -2

7 0
4 years ago
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