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Doss [256]
3 years ago
8

(34)(35) = A) 39 B) 99 C) 320 D) 620

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0
The right answer c and if it not then hope it helps you 
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Jill's car tires are spinning at a rate of 120 revolutions per minute. If her car tires' radii are each 14 inches, how far does
amid [387]

FInd the circumference of the tire:

C = 2 x PI x r

C = 2 x 3.14 x 14

C = 87.92 inches.

For every revolution of the tire it travels 87.92 inches.

In one minutes the car travels 87.92 x 120 = 10,550.4 inches.

In 5 minutes the car travels 10550.4 x 5 = 52,752 inches.

52,752 / 12 = 4,396 feet

1 mile = 5280 feet

4396 / 5280 = 0.833 miles

I calculated 3 different measurements. Use the one needed.

4 0
3 years ago
For what angles O between 0 and 360° is cos 0) = sin 0 true?
Westkost [7]

Answer:

Step-by-step explanation:

cos θ=sinθ

divide by cos θ

1=tan θ

tan θ=1=tan 45,tan (180+45)

θ=45°,225°

6 0
3 years ago
Evaluate each expression if x=-1, y=3, z=-4.<br> 3|z-x|+|2-y|
denpristay [2]
3|-4-(-1)|+|2-3|=10
Final answer: 10
5 0
3 years ago
7. Select True or False for each statement.
rewona [7]
A. True
B. False
C. False
D. False
E. True

B. Quadrant II contains ordered pairs of the form (negative number, positive number)
C. (-6,0) is located on the x-axis
D. The origin is not located on any of the quadrant. It’s in the center
8 0
3 years ago
Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

7 0
3 years ago
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