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seraphim [82]
3 years ago
10

Simplify the expression: (9 + 6m) + 21

Mathematics
1 answer:
slega [8]3 years ago
5 0

Answer:

<em>6m+30 </em>

Step-by-step explanation:

<u>Add 9 and 21</u>

<u>Hope this Helped!</u>

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Taylor and Jesse are buying a magazine for $3.75 and a snack for $2.49 what is s the total cost of the two items?
Kazeer [188]

Hey There!

The answer you are looking for is; $6.24!

Work:

You simply add $3.75 + $2.49 together.

Since .75 + .29 = 1.24, you carry the one over to the full dollar.

3 + 2 + 1 = 6.

= 6.24

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7 0
3 years ago
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What is the value of z in the equation 5(2z 4) = 0? -2 0 2 20
postnew [5]
5(2z X 4)=0 > 0
5(2z + 4)=0 > -2
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4 years ago
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P(-,3) , Q(7,-3) and R (4,1) are three points. show that PQ=2QR using distance formula. (please show the steps too :)​
solong [7]

Answer:

PQ is 10.

QR is 5.

Hence, PQ=2QR

Step-by-step explanation:

We have the three points P(-1, 3); Q(7, -3); and R(4, 1).

And we want to show that PQ=2QR.

In other words, we want to show that PQ/QR=2.

So, let's find PQ and QR. We will need to use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

To find PQ:

P is (-1, 3) and Q is (7, -3).

So, we will let P(-1, 3) be (x₁, y₁) and Q(7, -3) be (x₂, y₂).

Substitute the values into the distance formula. This yields:

d=\sqrt{(7-(-1))^2+(-3-3)^2

Evaluate:

d=\sqrt{(8)^2+(-6)^2

Evaluate:

d=\sqrt{64+36}=\sqrt{100}=10

So, the distance of PQ is 10.

And to find QR:

Q is (7, -3) and R is (4, 1).

Again, we will let Q(7, -3) be (x₁, y₁) and R(4, 1) be (x₂, y₂).

Substitute appropriately. So:

d=\sqrt{(4-7)^2+(1-(-3))^2

Evaluate:

d=\sqrt{(-3)^2+(4)^2

Evaluate:

d=\sqrt{9+16}=\sqrt{25}=5

So, the distance of QR is 5.

Therefore, it follows that:

\displaystyle PQ=2QR\Rightarrow \frac{PQ}{QR}=2\Rightarrow\frac{10}{5}\stackrel{\checmark}{=}2

And we have shown that PQ=2QR.

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One half of a number p is at least 100
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