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Vladimir79 [104]
4 years ago
13

Amy has $800 saved but withdraws $80 per week for gas and groceries​

Mathematics
1 answer:
JulijaS [17]4 years ago
6 0

Answer:

800-80w.

800-80(2)=800-160=640 left in 2 weeks.

800-80(3)=800-240=560

800-80(5)=800-400=400

800-80(7)=800-560=240

800-80(10)= 0. She has 10 weeks until all of her money is gone

Function: 800-80w

Range: 460

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What are the first five terms in the<br> recursive sequence defined by the<br> following?
kolezko [41]

The first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

<h3>Recursive function</h3>

Given the nth term of a recursive expression shown below

an =an-1 - 1.4

where

an-1 is the preceding term

a1 is the first term

an is the nth term

an-1 is

Given the following

a1 = 0

For the second term a2

a2 = 0 - 1.4

a2 = -1.4

For the third term a3

a3 = -1.4 - 1.4

a3 = -2.8

For the fourth term a4

a4 = -2.8 - 1.4

a4 = -4.2

For the fifth term a2

a5 = -4.2 - 1.4

a5 = -5.6

Hence the first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

Learn more on recursive function here: brainly.com/question/489759

#SPJ1

5 0
2 years ago
Estimate 815-281 to get the answer
Damm [24]

Answer:800-300

Step-by-step explanation:

since there is a 1 after the 8 it would go down to 800 and there is a 8 after the 2 so it would go up to 300

4 0
4 years ago
Read 2 more answers
Consider the equation below
s344n2d4d5 [400]

Answer: B

Step-by-step explanation:

Let's solve the given equation. Then we can see which other equation has the same answer.

-5n+31=-14n-5

36=-9n

n=-4

We need to fina another equation that gives n=4 as the answer.

A. Incorrect

3-6n+3n=-3+4-4n

3-3n=1-4n

n=-2

B. Correct

\frac{11}{4} n+2=-3+\frac{3}{2}n

\frac{5}{4}n=-5

n=-4

C. Incorrect

1=0.75n+3.25

-2.25=0.75n

n=-3

D. Incorrect

-1-22n=-20n-9

8=2n

n=4

7 0
3 years ago
A debate team of 4 members for a high school will be chosen randomly from a potential group of 15 students. Ten of the 15 studen
iragen [17]

Answer:

A) 0.1538

Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

We have to find the probability that for each member, one without experience is chosen. There is no replacents.

Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is \frac{10}{15}.

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is \frac{9}{14}.

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is \frac{8}{13}.

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is \frac{7}{12}.

What is the probability that none of the members chosen for the team have any competition experience?

This is

P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538

The correct answer is:

A) 0.1538

7 0
3 years ago
Use the distributive property to write an equivalent expression.
wlad13 [49]

Answer:

14x+35y-35

Step-by-step explanation:

distribute the 7 to each term

8 0
3 years ago
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