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melamori03 [73]
3 years ago
5

3a² + 11a – 42this is factoring in algebra 2 (high school) ​

Mathematics
1 answer:
N76 [4]3 years ago
3 0

To factor,

<h2>[[[</h2>

1) First multiply coefficient of a² and constant no,

That is,

3×(-42)=-126

Since the<u> resultant no is negative</u>, you should find two such factors of 126 <u>which</u> <u>will give us the coefficient of a (=11)</u> on subracting those factors.

2) Find the factor

126=2×3×3×7

=18×7

18 and 17 are factors of 126

Also,18-7 =11.

So they are required factors for factoring,

<h2>]]]</h2>

Once you have understood above steps you can solve on your own. All you need to do is split 11 into factors ,take common terms and you will get answer.

<u>Answer:</u>

3a²+11a-42

=3a²+(18-7)a -42

=3a²+18a-7a-42

=3a(a+6) -7(a+6)

=(a+6)(3a-7)

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3 years ago
21x-5=7+17x <br> Write it down step by step please
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21x−5=7+17x

21x+−5=7+17x

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Step 2: Subtract 17x from both sides.

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Step 4: Divide both sides by 4.

\frac{4x}{4} = \frac{12}{4}

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