Answer:
176 square yards
Step-by-step explanation:
<u><em>The picture of the question in the attached figure N 1</em></u>
we know that
The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)
see the attached figure N 2 to better understand the problem
step 1
Find the area of the two trapezoids (#1 and #2)
simplify
we have
substitute
step 2
Find the area of the two smaller rectangles (#3 and #4)
we have
substitute
step 3
Find the area of the walkway around the rectangular pool
Answer:
1.44... ( 1.4 recurring) or 1 4/9.
Step-by-step explanation:
212x−34(2x+5)=38
212x - 68x - 170 = 38
144x = 38 + 170 = 208
x = 208/144 = 1.44....
To solve this problem you must apply the proccedure shown below:
1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
(y^2/a^2)+(x^2/b^2)=1
2. You have the distance from the center of the ellipse to the focus:
c=12, therefore, you can calculate the value of b, the minor radius:
c^2=a^2-b^2
b=√(13^3-12^2)
b=5
3. Therefore, the equation is:
a^2=169
b^2=25
(y^2/169)+(x^2/25)=1
The answer is: (y^2/169)+(x^2/25)=1
Yes you can use this equation to solve this problem
The GCF of 72, 48, and 36 is 12.
I hope this helps, and have a good night! :D