Damage to the parked car is $5,400. Damage to the store is $12,650. Total damage is calculated as follows :
Total damage = damage to the car + damage to the store Substitute the values in the formula :
Total damage = $5,400 + $12,650 = $18,050. Total damage is $18,050.
The insurance company will cover a maximum of $15,000. The remaining amount of the damage has to be paid by Kurt. The remaining amount is calculated as :
Amount paid by Kurt = Total damage – amount paid by insurance company
Substitute the values in the formula :
Amount paid by Kurt = $18,050 - $15,000 = $3,050
Therefore, he will have to pay the remaining $3,050
Answer:
The multiple choices are:
$5,589.04
$7,452.05
$4,890.41
$5,876.71
$6,410.96
Amount invested in K is $6,410.96
Explanation:
L+K=12,000
from the return perspective
0.0975=K/12000*0.0805+L/12000*0.117
K=12000-L
Substitute for K in the second equation
0.0975=(12000-L)/12000*0.0805+L/12000*0.117
0.0975=(966-0.0805L)/12000+0.117L/12000
0.0975=(966-0.0805L+0.117L)/12000
12000*0.0975=966+0.0365
L
1170
-966=0.0365L
204=0.0365L
L=204/0.0365
L=$ 5,589.04
K=$12,000-$ 5,589.04
K=$6,410.96
<span> Dose this help. An innovation, service, or feature intended to make a company or product attractive to customers. (In marketing) </span>
Answer:
a. $880.74
b. 13 years
Explanation:
a. Conversion ratio = Current Value of bond / Conversion price = 1,000 / 93.4 = 10.71
Conversion price of bond = 10.71 × 28.60 = $306.31
Coupon = Par value of bond * Coupon rate = $1,000 * 6.4% = $64
Present value of straight debt is calculated below:
Present Value = $64 × [1-(1+7.4%)^-30 / 7.4%] + [$1,000 / (1+7.4%)^30]
= $64*11.93 + $117.46
= $763.28 + $117.46
= $880.74
.
Therefore, the minimum value of bond is $880.74
b. Conversion ratio = 10.71
Current stock price = $28.6
Suppose number of year the stock will take to reach above $1,140 is t.
Conversion value = Current stock price * Conversion ratio*(1+10.8%)^t
$1,140 = $28.6 * 10.71 * (1.108)^t
(1.108)^t = 3.7218
t = 12.8145 year.
t = 13 years
<span>I believe the answer for you question would be life-cycle</span>