6th grade math help me, please:)))

Mathematics

1 answer:

Lesechka [4]3 years ago

5 0

Step-by-step explanation:

Hi there!!! 

The answer is option A. 

reason look in picture. 

if you want to solve it just cross multiply it,

 $60x = 240000 \times 100$ 

or,

 $x = 24000000 \div 60$ 

and the answer would be 400000.

Hope it helps...

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The equation of a quadratic is =2^2+3−2and after you factorizing 2^2+3−2=0you got x = -2 and x = 1/2 and the curve crosses the y

Lelechka [254]

Given the next quadratic function:

$y=2x^2+3x-2$

to sketch its graph, first, we need to find its vertex. The x-coordinate of the vertex is found as follows:

$x_V=\frac{-b}{2a}$

where a and b are the first two coefficients of the quadratic function. Substituting with a = 2 and b = 3, we get:

$\begin{gathered} x_V=\frac{-3}{2\cdot2} \\ x_V=-\frac{3}{4}=-0.75 \end{gathered}$

The y-coordinate of the vertex is found by substituting the x-coordinate in the quadratic function, as follows:

$\begin{gathered} y_V=2x^2_V+3x_V-2 \\ y_V=2\cdot(-\frac{3}{4})^2+3\cdot(-\frac{3}{4})-2 \\ y_V=2\cdot\frac{9}{16}+3\cdot(-\frac{3}{4})-2 \\ y_V=\frac{9}{8}-\frac{9}{4}-2 \\ y_V=-\frac{25}{8}=-3.125 \end{gathered}$

The factorization indicates that the curve crosses the x-axis at the points (-2, 0) and (1/2, 0). We also know that the curve crosses the y-axis at (0,-2). Connecting these points and the vertex (-0.75, -3.125) with a U-shaped curve, we get:

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1 year ago

LMNP is a rectangle. If LN = 9x – 14 and MP = 7x + 4, find the values of x, LN, and MP.

Fittoniya [83]

I am thinking of a rectangle that has the two sides parallel to one another. Set the two functions equal to one another, so

9x-14=7x+4

After a bunch of algebra and math magic, 2x=18 => x=9

So if you just insert 9 into both equations, both will end up with a value of 67, so it ends up looking like a right triangle. Don't do that. Instead, to find the rectangle widths, use 9x-4 (+10 added to intercept) instead, while keeping 7x+4, so that the intercepts match.

LN) 9x-4 = 9(9)-4 = 81-4 = 77
MP) 7(9)+4 = 63+4 = 67

*If you are also looking for the diagonals, use Pythagorean Theorem 77^2+67^2=(hypotenuse)^2*

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2 years ago

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}