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3 years ago

The following relation is a function: {(-8, – 9), (-4, 5), (1, 5), (4, 7)}

Mathematics

1 answer:

Nookie1986 [14]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

The following relation is a function. When graphed, it passes the vertical line test, and you don't go across any two points at the same time. So therefore, it is a function. Another easy way to determine if the relation is a function is by taking a look at the x-coordinates. If any x-coordinates are the same, then it's not a function. If all x-coordinates are the same, then it's a function.

Hope this helps. Please mark brainliest.

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Simon drove through some roadworks where the speed limit was 50 mph. Two cameras recorded the time taken to travel 1200 m throug

Tom [10]

Answer:

$Speed = 21.43m/s$

Step-by-step explanation:

Given

$Distance = 1200m$ -- of the roadworks

$Time\ Recorded = 56s$

Required

Determine the speed

In this case:

$Speed = \frac{Distance\ of\ Roadword}{Time\ Captured}$

$Speed = \frac{1200m}{56s}$

$Speed = 21.43m/s$ --- approximated

3 0

3 years ago

Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.

Maslowich

Answer:

16 pi cubic units

Step-by-step explanation:

Given that a region is bounded by

$f(x)=√x, y=0, x=1, x=4$

And the region is rotated about x axis.

We can find that here radius would be y value and height would be dx

So volume would be as follows:

If f(x) is rotated about x axis volume

= $\pi \int\limits^b_a {y^2} \, dx \\=\pi \int\limits^4_1 {x} \, dx\\=\pi *x^2 ^4_1\\= \pi*16-1\\=15\pi$

cubic units.

4 0

3 years ago

Two points on L1 and two points on L2 are given. Use the slope formula to determine if lines L1 and L2 are parallel, perpendicul

vlada-n [284]

Answer:

The lines L1 and L2 neither parallel nor perpendicular

Step-by-step explanation:

* Lets revise how to find a slope of a line

- If a line passes through points (x1 , y1) and (x2 , y2), then the slope

of the line is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- Parallel lines have same slopes

- Perpendicular lines have additive, multiplicative slopes

( the product of their slopes is -1)

* Lets solve the problem

∵ L1 passes through the point (1 , 10) and (-1 , 7)

- Let (1 , 10) is (x1 , y1) and (-1 , 7) is (x2 , y2)

∴ x1 = 1 , x2 = -1 and y1 = 10 , y2 = 7

∴ The slope of L1 is $m1 = \frac{7-10}{-1-1}=\frac{-3}{-2}=\frac{3}{2}$

∵ L2 passes through the point (0 , 3) and (1 , 5)

- Let (0 , 3) is (x1 , y1) and (1 , 5) is (x2 , y2)

∴ x1 = 0 , x2 = 1 and y1 = 3 , y2 = 5

∴ The slope of L2 is $m2=\frac{5-3}{1-0}=\frac{2}{1}=2$

∵ m1 = 3/2 and m2 = 2

- The two lines have different slopes and their product not equal -1

∴ The lines L1 and L2 neither parallel nor perpendicular

7 0

3 years ago

Question 15 of 40

PilotLPTM [1.2K]

Answer:

Option C: n = 32; p^ = 0.4

Step-by-step explanation:

The normal curve can be used in this case if; np ≥ 10 or n(1 - p) ≥ 10

A) For n = 28 and p = 0.3;

np = 28 × 0.3 = 8.4 < 10

Thus, it can't be used.

B) For n = 28 and p = 0.9;

np = 28 × 0.9 = 25.2 > 10 Ok

n(1 - p) = 28(1 - 0.9) = 2.8 Not Ok

Thus, it can't be used

C) For n = 32 and p = 0.4

np = 32 × 0.4 = 12.8 > 10 Ok

n(1 - p) = 32(1 - 0.4) = 19.2 > 10 Ok

Thus, it can be used

D) For n = 32 and p = 0.2

np = 32 × 0.2 = 6.4 < 10 Not Ok

Thus it can't be used.

4 0

3 years ago

Which is a stretch of an exponential decay function? f(x) = O f(x) = O Rx) = O f(x)=

zhannawk [14.2K]

B I think but I don’t know

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3 years ago

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