bearing in mind that, the geometric sequence is "convergent" only when |r|<1, or namely "r" is a fraction between 0 and 1.
Please Help! Will give Brainliest! Will give 50 points! Just please help!.The equation of function h is h(x) = 1/2(x - 2)^2. The
table shows some of the values of function m.
Part A: What is the value of h(4) - m(16)?
Part B: If both of these fonctions are graphes on the same coordinate plane, how far apart are the y-intercepts?
Part C: What values of x does m(x) excess h(x)?
Part A: What is the value of h(4) - m(16)?
Part B: If both of these fonctions are graphes on the same coordinate plane, how far apart are the y-intercepts?
Part C: What values of x does m(x) excess h(x)?
1 answer:
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bearing in mind that, the geometric sequence is "convergent" only when |r|<1, or namely "r" is a fraction between 0 and 1.
-3 | 1 0 0 0 0 243 
coefficients of the polynomial you're dividing
. | drop down the leading coefficient
- - - - - - - - - - - - - - - - - - -
. | 1
On the left side of the frame, we write -3 because we're dividing by
. (The algorithm is followed for division of a polynomial by a factor of 
.) Since we're dividing a degree 5 polynomial by a degree 1 polynomial, we expect to get a degree 4 polynomial.
-3 | 1 0 0 0 0 243
. | -3 multiply -3 by 1, write in next column, add to 0
- - - - - - - - - - - - - - - - - - -
. | 1 -3
Repeat step for the remaining columns.
-3 | 1 0 0 0 0 243
. | -3 9
- - - - - - - - - - - - - - - - - - -
. | 1 -3 9
-3 | 1 0 0 0 0 243
. | -3 9 -27
- - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27
-3 | 1 0 0 0 0 243
. | -3 9 -27 81
- - - - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27 81
-3 | 1 0 0 0 0 243
. | -3 9 -27 81 -243
- - - - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27 81 0
which translates to
So the bottom row of the frame gives the coefficients of each term in the quotient by descending order. Since the last coefficient is 0, this means the remainder upon division vanishes, i.e.
is exactly divisible by 
.
- - -
Another way to get the same result is to use a well-known result: for
,
and in this case
and 
. |
- - - - - - - - - - - - - - - - - - -
. | 1
On the left side of the frame, we write -3 because we're dividing by
-3 | 1 0 0 0 0 243
. | -3
- - - - - - - - - - - - - - - - - - -
. | 1 -3
Repeat step for the remaining columns.
-3 | 1 0 0 0 0 243
. | -3 9
- - - - - - - - - - - - - - - - - - -
. | 1 -3 9
-3 | 1 0 0 0 0 243
. | -3 9 -27
- - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27
-3 | 1 0 0 0 0 243
. | -3 9 -27 81
- - - - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27 81
-3 | 1 0 0 0 0 243
. | -3 9 -27 81 -243
- - - - - - - - - - - - - - - - - - - - -
. | 1 -3 9 -27 81 0
which translates to
So the bottom row of the frame gives the coefficients of each term in the quotient by descending order. Since the last coefficient is 0, this means the remainder upon division vanishes, i.e.
- - -
Another way to get the same result is to use a well-known result: for
and in this case