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Komok [63]
3 years ago
13

Find the equation of a line that is PERPENDICULAR to y = 1/3 x -2 & passes through the point ( 3, 2 ). (CHECK PIC FOR ANSWER

CHOICES)

Mathematics
1 answer:
densk [106]3 years ago
3 0

Answer:

The answer to your question is the letter b)    y = -3x + 11

Step-by-step explanation:

Data

Original line  y = 1/3x - 2

Point = (3, 2)

New line = ? (perpendicular)

Process

1.- Get the slope of the original line

The slope is the coefficient of the x in the line equation.

       y = 1/3x - 2

       slope = m = 1/3

2.- Find the slope of the new line

       new slope = -3  (because the lines are perpendicular)

3.- Find the equation of the new line

         y - y1 = m(x - x1)

 x1 = 3    y1 = 2

-Substitution

        y - 2 = -3(x - 3)

-Simplification

        y - 2 = -3x + 9

        y = -3x + 9 + 2

-Result

       y = -3x + 11

         

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