Question

Y=_x+4 x + 2y = 8 How many solutions dose this linear system have

Answer 1

Answer:

X=-1, y=4

Step-by-step explanation:

$y = x + 4 \\ x + 2y = 8 \\ = = = = = = = = = = = = \\ y - x = 4 \\ x + 2y = 8$

by using eliminating property

$3y = 12 \\ y = \frac{12}{3} = 4$

by substitution

X=-1