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ddd [48]
4 years ago
8

I WILL AWARD BRAINLIEST!! PLEASE HELP!!

Mathematics
1 answer:
Natalka [10]4 years ago
5 0

Answer:

speed = distance/time, so

distance = speed * time

Walking:

d = speed * time

d1 = 33 mph * x hours = 33x miles

Bicycling:

d = speed * time

d2 = 93 mph * (5 - x) hours = 93(5 - x) miles = (465 - 93x ) miles

The total distance traveled is the distance walked plus the distance bicycled

d = d1 + d2

d = 33x + 465 - 93x

d = -60x + 465

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3x + y - z= -6<br> 2x - y + 2z = 8<br> 4x + y - 3z = -21
Flauer [41]

Answer:

x=-1

y=4

z=7

Step-by-step explanation:

3x + y - z= -6(1)

2x - y + 2z = 8(2)

4x + y - 3z = -21(3)

(1)+(2): 5x+z=2(4)

(2)+(3): 6x-z=-13(5)

(4)+(5): 11x=-11

x=-1

so z=2-5x=7

y=-6-3x+z=4

8 0
3 years ago
Yara saved 440$. She spent 3/4 of it on a tablet. How much money did yara spend on the tablet
TiliK225 [7]
440 times 3/4=330
$330
5 0
3 years ago
Read 2 more answers
3. At the start of summer, Ben has $250 . He takes a summer
earnstyle [38]

Answer:

Week 4

Step-by-step explanation:

Ben has $250 in the beginning.  He saves $150 per week.

y = 150x + 250

Tim has $1,650 in the beginning.  He spends $200 per week.

y = 1650 - 200x

We are trying to find which x-value produces the same y-value for both equations.  You can do this by setting both equations equal to each other.

150x + 250 = 1650 - 200x

(150x + 250) + 200x = (1650 - 200x) + 200x

350x + 250 = 1650

(350x + 250) - 250 = (1650) - 250

350x = 1400

(350x)/350 = (1400)/350

x = 4

By week 4, they will have the same amount of money.

3 0
3 years ago
twice the sum of a number and 2 is equal to three times the difference of the number and 3. Find the number
Lana71 [14]
2(x+2)=3(x-3)
2x+4=3x-9
2x=3x-13
-x=-13
x=13

The number is 13
3 0
3 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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