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3 years ago

RM = x + 3 and MS = 2x –1 x=_ and RM = HELP

Mathematics

1 answer:

tino4ka555 [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Given RM = x+3 and MS = 2x-1, if M is on between R and S, then RM = MS

x+3 = 2x-1

collect like terms;

x - 2x = -1-3

-x = -4

Divide both sides by -1

-x/-1 = -4/-1

x = 4

Since RM = x+3, substitute x = 4 into the expression to get the lrngth of Rm.

RM = 4+3

RM = 7

Hence x = 4, RM = 7

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I NEED HELP ASAP PLEASEEEE

spin [16.1K]

Answer:

Step-by-step explanation:

1) Find the Mean of all the numbers.

3+4+5+7+10+12+15=56

56/7=8 mean is 8

Now We Calculate Standard Deviation:

S= $\sqrt{(3-8)^2+(4-8)^2+(5-8)^2+(7-8)^2+(10-8)^2+(12-8)^2+(15-8)^2}$

You take each number from the problem i.e 3,4,5...

and then you subtract the mean from it and then square it.

S= $\sqrt{(-5)^2+(-4)^2+(-3)^2+(-1)^2+(2)^2+(4)^2+(7)^2}$

S= $\sqrt{25+16+9+1+4+16+49}$

S= $\sqrt{120}$

S= $\sqrt{120}/7$

7 is the amount of data units given in the problem.

120/7=17.1428571429

$\sqrt{17.1428571429}$ =4.1403933560541

Nearest hundredth=4.14

5 0

3 years ago

$600 at 4% for 9 months.

NISA [10]

It’s like 24 if your asking how much 4% of 600 is.

3 0

3 years ago

In a list of households, own homes and do not own homes. Four households are randomly selected from these households. Find the p

labwork [276]

Complete Question

In a list of 15 households, 9 own homes and 6 do not own homes. Four households

are randomly selected from these 15 households. Find the probability that the

number of households in the sample which own homes is exactly 3

Answer:

Step-by-step explanation:

From the question we are told that

The number of household is n = 15

The number of household that own homes is k = 9

The number of household that do not own homes is u = 6

The number of households randomly selected is q = 4

Generally the number of ways of selecting 3 household from the total number of 9 households that own homes is mathematically represented as

$A = ^{k} C_ 3$

Here C stands for combination hence we would be making use of the combination feature in our calculator

=> $A = ^{9} C_ 3$

=> $A =84$

Generally the number of ways of selecting 1 household from the total number of 6 households that do not own homes is mathematically represented as

$B = ^{u}C_1$

=> $B = ^{6}C_1$

=> $B = 6$

Generally the number of ways of selecting 4 household from the total number of 15 households on the list is mathematically represented as

$D = ^{n}C_4$

=> $D = ^{15}C_4$

=> $D = 1365$

Generally the probability that the number of households in the sample which own homes is exactly 3 is mathematically represented as

$P( X = 3) = \frac{A * B}{D}$

=> $P( X = 3) = \frac{85 * 6}{1365}$

X is here represent the number of household in the selected sample that own homes

=> $P( X = 3) = 0.3736$

7 0

3 years ago

Please help me also this is not part of a test it's fine

STatiana [176]

<u>Answer:</u>

<h2>D. 72 inches</h2><h2>E. 77 inches</h2>

<u>Explanation:</u>

5.65 ft = 67.8 in

given: Daniel's dad is <u>more than</u> 5.65 ft

hence 72 in and 77 in are the answers that apply

3 0

3 years ago

The smaller of two numbers is five less than 1/3 the larger number. Half the larger added to the smaller is 10. Find the numbers

qwelly [4]

The numbers are 1 and 18

<em><u>Solution:</u></em>

Let the smaller number be "x"

Let the larger number be "y"

Given that smaller of two numbers is five less than $\frac{1}{3}$ the larger number

smaller number = one - third of larger number - 5

$x = \frac{1}{3} \times y - 5\\\\x = \frac{y - 15}{3}\\\\$

3x = y - 15

y = 3x + 15 ------- eqn 1

Half the larger added to the smaller is 10

$\frac{1}{2}y + x = 10\\\\\frac{y + 2x}{2} = 10$

y + 2x = 20 ------- eqn 2

Let us solve eqn 1 and eqn 2

Substitute eqn 1 in eqn 2

3x + 15 + 2x = 20

5x = 20 - 15

5x = 5

From eqn 1,

y = 3(1) + 15 = 18

Thus the numbers are 1 and 18

6 0

3 years ago

RM = x + 3 and MS = 2x –1 x=_______ and RM =______ HELP

RM = x + 3 and MS = 2x –1 x=_ and RM = HELP