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Paladinen [302]
4 years ago
7

Mr brown bought a lot that ia half as long and twice as wide Mrs.Rockwell's lot.How does the area of his lot compare to the area

of Mrs.Rockwell's lot? Explain how you know
Mathematics
1 answer:
prohojiy [21]4 years ago
7 0

Answer:

Area of Mrs. Rockwell's lot is equal to the area of Mr. Brown's lot

Step-by-step explanation:

We can suppose the dimensions of Mrs. Rockwell's lot to be:

Length = x

Width = y

Then, we can write the dimensions of Mr. Brown's lot as:

Length = half as long as Mrs. Rockwell's lot

Length = 0.5x

Width = twice as wide as Mrs. Rockwell's lot

Width = 2y

Area of Mrs. Rockwell's lot = Length * Width

                                             = x*y  

Area of Mrs. Rockwell's lot = xy

Area of Mr. Brown's lot = 0.5x*2y

Area of Mr. Brown's lot = xy

<u>Area of Mrs. Rockwell's lot </u><u>is equal</u><u> to the area of Mr. Brown's lot, as calculated above</u>.

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Answer:

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Step-by-step explanation;

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Answer:

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Step-by-step explanation:

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-------------

16 = 4

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I am joyous to assist you anytime.

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Answer:

A

Step-by-step explanation:

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3 years ago
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Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

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\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

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and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

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2 years ago
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aksik [14]

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7 0
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