All categories

4 years ago

5.62 as a mixed number in simplest form

Mathematics

2 answers:

Andrej [43]4 years ago

6 0

5.62 would be 5 62/100 then you can simplify the fraction down
62/100 - 31/50
5 31/50
Hope I helped :)

Gnoma [55]4 years ago

6 0

The answer is 5 31/50 as a simplest form

You might be interested in

What are the solutions of the equation 4x2 3x = 24 – x? –3, 2, or 4 –3 or 2 –2, 3, or 4 –2 or 3

Sedbober [7]

Answer:

2 and - 3

Step-by-step explanation:

I've attached my work...

- 4 + 20 / 8 -> 16/8 = 2

- 4 - 20 / 8 -> -24/8 = -3

Please give me feedback on my repsomse by commenting,

any way i can improve showing my work?

Hope it helps, let me know if you have questions !

Have a nice rest of your day :)

5 0

2 years ago

2x + 9<br> 8x + 1<br> Solve for x

Leto [7]

2x+9+8x+1=180

2x+8x+9+1=180

10x+10=180

10x=170

X=17

8 0

4 years ago

Por qué el aumento del nivel del mar

raketka [301]

Answer:

el aumento es debido a los icebergs derritiendose

losiento por mi español

4 0

3 years ago

Mr. Richard needs blocks of wood that are 6 inches long. He found logs of wood in their backyard that have the

Stolb23 [73]

Answer:

<h2>1 ) A question of a log with inches is asked.</h2><h2>2) The inches of the logs.</h2><h2>3)Multiplication. </h2><h2>4) Multiply six times every number to get the actual inches of the one given.</h2><h2 />

6 0

3 years ago

Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo

NNADVOKAT [17]

Answer:

$P(a | e') = 0.22$

$P(b | e') = 0.28$

$P(c | e') = 0.33$

$P(a | e' , d' , b') = 0.57$

Step-by-step explanation:

From the question we are told that

The probabilities are

Supplier chosen A B C

Probability P(a) = 0.20 P(b) = 0.25 P(c) = 0.15

D E

P(d) = 0.30 P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(a | e') = \frac{P (a \ and \ e')}{P(e')}$

$P(a | e') = \frac{P (a)}{P(e')}$

$P(a | e') = \frac{P (a)}{1- P(e)}$

=> $P(a | e') = \frac{ 0.20}{1- 0.10}$

=> $P(a | e') = 0.22$

Generally the new probability of companies B being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(b | e') = \frac{P (b \ and \ e')}{P(e')}$

$P(b | e') = \frac{P (b)}{P(e')}$

$P(b | e') = \frac{P (b)}{1- P(e)}$

=> $P(b | e') = \frac{ 0.25}{1- 0.10}$

=> $P(b | e') = 0.28$

Generally the new probability of companies C being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(c | e') = \frac{P (c \ and \ e')}{P(e')}$

$P(c | e') = \frac{P (c)}{P(e')}$

$P(c | e') = \frac{P (c)}{1- P(e)}$

=> $P(c | e') = \frac{ 0.15}{1- 0.10}$

=> $P(c | e') = 0.17$

Generally the new probability of companies D being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(d | e') = \frac{P (d \ and \ e')}{P(e')}$