If it is 0.2 inches less, just subtract.
0.6 - 0.2 = 0.4
Answer:
its 3
Step-by-step explanation:
Answer:
No. √14 + 6.2 is more than 3π - 8.2
Step-by-step explanation:
√14 + 6.2
√20.2
≈ 4.494
π ≈ 3.14159
3(3.14159) - 8.2
9.42577 - 8.2
1.22477
Therefore, the answer is no.
Answer: sin u = -5/13 and cos v = -15/17
Step-by-step explanation:
The nice thing about trig, a little information goes a long way. That’s because there is a lot of geometry and structure in the subject. If I have sin u = opp/hyp, then I know opp is the opposite side from u, and the hypotenuse is hyp, and the adjacent side must fit the Pythagorean equation opp^2 + adj^2 = hyp^2.
So for u: (-5)^2 + adj^2 = 13^2, so with what you gave us (Quad 3),
==> adj of u = -12 therefore cos u = -12/13
Same argument for v: adj = -15,
opp^2 + (-15)^2 = 17^2 ==> opp = -8 therefore sin v = -8/17
The cosine rule for cos (u + v) = (cos u)(cos v) - (sin u)(sin v) and now we substitute: cos (u + v) = (-12/13)(-15/17) - (-5/13)(-8/17)
I am too lazy to do the remaining arithmetic, but I think we have created a way to approach all of the similar problems.
The distance between the two points in the line segment A_F is 6.3 units
<h3>Distance Between Two Points</h3>
Distance between two points is the length of the line segment that connects the two given points. Distance between two points in coordinate geometry can be calculated by finding the length of the line segment joining the given coordinates. Let us understand the formula to find the distance between two points in a two-dimensional and three-dimensional plane.
The distance between any two points is the length of the line segment joining the points. There is only one line passing through two points. So, the distance between two points can be calculated by finding the length of this line segment connecting the two points.
The data points are;
Distance between points A and F 6.3 units
Learn more distance between two points here;
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