How do you solve |2x-5|=4.

A rocket is launch from atop a 74 foot cliff with an initial velocity of 113 ft/s the height of the rocket above the ground at t

EleoNora [17]

Answer: We will use the QUADRATIC FORMULA.

x=7.6659375

Step-by-step explanation:

Use the Quadratic formula

a=-16,b=113,c=74

And then use the quadratic formula and you get x=7.6659375

6 0

3 years ago

Angle PQRPQR and angle TQVTQV are vertical angles. The measures of the two angles have a sum of 100^{\circ}100

Kitty [74]

10005ssduduc Vicdhdjdjd

7 0

3 years ago

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The car company is trying to make a car that is more fuel efficient, meaning it takes less force to get the car to move. Explain

agasfer [191]

Step-by-step explanation:

<h2><em><u>Fuel technologies and advanced motor oil innovation</u></em></h2><h2 /><h2><em><u>Fuel technologies and advanced motor oil innovationExxonMobil is committed to developing and supplying quality fuels, which is why we have an entire active research organization dedicated to ensuring that the product pumped into your vehicle is the latest technology in industry innovation.</u></em></h2><h2 /><h2><em><u>Fuel technologies and advanced motor oil innovationExxonMobil is committed to developing and supplying quality fuels, which is why we have an entire active research organization dedicated to ensuring that the product pumped into your vehicle is the latest technology in industry innovation.Additionally, our breakthrough lubricants offer drivers a longer interval between oil changes and improved engine efficiency, while still providing outstanding performance and protection. Our specially formulated synthetic motor oil products are tailored to improving engine function, whether it be for greater durability, better wear protection or running a cleaner engine.</u></em></h2>

4 0

3 years ago

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5 ports Use absolute value to express the distance between -12 and -15 on the number line. |-12 - (-15) = -27

zloy xaker [14]

Answer:

$Distance = 3$

Step-by-step explanation:

Given

-12 and -15

Required

Solve the difference

The question you posted included the solution. However, the solution is incorrect;

The absolute difference is represented as:

$Difference = \vert a - b \vert$

In this case:

$a = -12$

$b = -15$

So, the distance is calculated as:

$Distance = |-12 - (-15)|$

Open bracket

$Distance = |-12 +15|$

$Distance = |3|$

$Distance = 3$

3 0

3 years ago

Which function has a phase shift of pi/2 to the right?

Bess [88]

If it helps you any

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\end{array}$

$\bf \begin{array}{llll}

\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

so.. check coefficients C and B for the horizontal shift

7 0

4 years ago

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