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Stella [2.4K]
3 years ago
14

Thanks again for the answer :)

Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0
X=.5________________
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I need help in this question
iren [92.7K]

Answer:

128

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the prime factorazation of 31
lutik1710 [3]

Answer:

31 is a prime number.

How to tell if a number is prime: estimate the square root. In this case, we know the square root of 31 is between 5 and 6 and it isn’t divisible by either of those. If it is divisible by a number higher than it’s square root, the other factor must be lower. Is it divisible by 4 or 2? no, because it isn’t an even number. It’s not divisible by 3, because there’s a remainder of 1 if you try. You’ve eliminated all numbers less than the square root, so it is prime


7 0
4 years ago
Read 2 more answers
8 (3g+2)-3g=3 (5g-4)-2
serious [3.7K]
<span>8 (3g+2)-3g=3 (5g-4)-2
Multiply the number outside the exponent with the numbers inside the parenthisis.
24g+16-3g=15g-12-2
Subtract 3g from 24g
21g+16=15g-12-2
Add 15g to 21g
36g+16=-12-2
Subtract 2 from -12
36g+16=-14
Subtract 16 from -14
36g=30
Final Answer: g=0.83 (The three goes on infinitely.)
</span><span>
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7 0
3 years ago
An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s
Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, s=120\ ft/s

The height 'h' of the debris above the ground is given as:

h(t)=-16t^2+120t

As per question, h(t)=56\ ft. Therefore,

56=-16t^2+120t

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0

Using quadratic formula to solve for 't', we get:

t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s

Therefore, the debris will reach a height of 56 ft twice.

When time t=0.5\ s during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at t=7\ s, the height is 56 ft.

5 0
3 years ago
What is the output of the function when the input is 0?
ohaa [14]

Answer:

The input is zero, the output is -1

Step-by-step explanation:

We want to know the y value when the x value is zero

When x =0, y = -1

The input is zero, the output is -1

7 0
2 years ago
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