Question

A car rental agency rents cars for $26.20 per day plus $0.35 per mile driven. Your travel budget is

Answer 1

Answer:

26.20 + 0.35m ≤ 200

Step-by-step explanation:

Let m = number miles of the driven

Given

$26.20 is the initial

Every mile cost $0.35

We have :

26.20 + 0.35m ≤ 200

Answer 2

Answer: The maximum number of miles would be 496 miles.

Step-by-step explanation:

Let the number of miles be 'm'.

Cost of per day = 426.20

Number of day = 1

Cost of per mile = $0.35

Total travel budget = $200

According to question, the inequality would be

$26.20\times 1+0.35x\leq 200\\\\26.20+0.35x\leq 200\\\\0.35x\leq 200-26.20\\\\0.35x\leq 173.8\\\\x\leq \dfrac{173.8}{0.35}\\\\x\leq 496.57$

Hence, the maximum number of miles would be 496 miles.