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Sati [7]
3 years ago
11

What is the measure of the hypotenuse?

Mathematics
2 answers:
Scilla [17]3 years ago
5 0

Answer:

Step-by-step explanation:

using pythagoras theorem which says the square root of the sum of the  square of the opposite  side  and the square of the adjacent side would give the value of the hypotenuse

hyp^2 = opp^2 + adj^2

i dont have the square root symbol but u can solve it either way :

you can input the values given and then collect like terms or u can take the square root of the right side. The right angle would always face the hypotenuse which is the longest side.

hyp = x

x^2=(5)^2 +(12)^2

x^2= 25 +144

x^2=169

take the square of both sides to get your value for x

x= 13

SOVA2 [1]3 years ago
3 0
<h2><em>Answer:</em></h2><h3><em>1</em><em>3</em></h3>

<em>solution \\ hypotenuse = x \\ base = 12 \\ perpendicular = 5 \\ using \: pythagoras \: theorem \\  {h}^{2}  =  {p}^{2}  +  {b}^{2}  \\ or \:  {x}^{2}  =  {5}^{2}  +  {12}^{2}  \\ or \:  {x}^{2}  = 25  + 144 \\ or \:  {x}^{2}  = 169 \\ or \: x =  \sqrt{169}  \\ x = 13 \\</em>

<em>hope </em><em>it</em><em> helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Estimate StartRoot 37 EndRoot 37 to the nearest tenth. Then locate StartRoot 37 EndRoot 37 on a number line.
Vesnalui [34]

Estimating value of √37.

We know that

6^{2} = 36 and 7^{2} =49, so

6 < √37 < 7

If we take the average of 6 and 7, we get

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Since, 6.5^{2} = 42.25

6 < √37 < 6.5

If we take the average of 6 and 6.5 , we get

\frac{6+6.5}{2}  = \frac{12.5}{2} = 6.25

Since, 6.25^{2} = 39.0625

6 < √37 < 6.25

If we take the average of 6 and 6.25 , we get

\frac{6+6.25}{2}  = \frac{12.25}{2} = 6.125

Since, 6.125^{2} = 37.515625

6 < √37 < 6.125

If we take the average of 6 and 6.125 , we get

\frac{6+6.125}{2}  = \frac{12.125}{2} = 6.0625

Since, 6.0625^{2} = 36.75390625

6.0625 < √37 < 6.125

If we take the average of 6.0625 and 6.125 , we get

\frac{6.0625+6.125}{2}  = \frac{12.125}{2} = 6.09375

Since, 6.09375^{2} = 37.1337890625

6.0625 < √37 < 6.09375

If we take the average of 6.0625 and 6.09375 , we get

\frac{6.0625+6.09375}{2}  = \frac{12.15625}{2} = 6.078125

Since, 6.078125^{2} = 36.943603515625

6.078125 < √37 < 6.09375

If we take the average of 6.078125 and 6.09375 , we get

\frac{6.078125+6.09375}{2}  = \frac{12.171875}{2} = 6.0859375

Since, 6.0859375^{2} = 37.03863525390625

Therefore,

√37 ≈ 6.0859375.

And if we round it to the nearest tenth, we get

√37 ≈ 6.1


Locating √37 on number line.

In order to locate √37 on number line first draw a line 0 to 6 on number line.

Then draw a perpendicular line segment of 1 unit on number 6 on number line.

Join the number 0 on the number line by the top point of perpendicular line segment on number 6 we drew in above step.

Finally, draw a curve by taking radius as Hypotenuse of the right trinagle form in the diagram shown.

The curve would cut the number line exactly at √37 on number line.

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3 years ago
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4 0
3 years ago
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Aliun [14]
We know that

If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment. (Intersecting Secant-Tangent Theorem)

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the answer is

RT=14.49 in

4 0
3 years ago
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