Answer:g=2
3g+3-3=9-3
3g=6
3g/3=6/3
g=2
Step-by-step explanation:
there you go
I positive 15 and negative 15, in effect the absolute value function just removed negative signs
Answer:
p= -1
Step-by-step explanation:
gradient=<u>y</u><u>²</u><u>-</u><u>y</u><u>¹</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>x²-x¹
-1 =<u>p</u><u>-</u><u>2</u>
<u> </u><u> </u><u> </u><u> </u><u> </u>9-6
-1=<u>p</u><u>-</u><u>2</u>
<u> </u><u> </u><u> </u><u> </u><u> </u> 3
multiply both sides by 3 to remove the denominators
-1×3=p-2
-3=p-2
put the like terms together
-3+2=p
-1=p
I don't think I understand what you mean, but I will guess. A quadrilateral must have 4 sides to it and have 4 vertices (corners).
Answer:
x-intercepts: (2, 0) and (−5, 0)
y-intercept: (0, −10)
Step-by-step explanation:
y = x^2 + 3x − 10
y-intercept when x = 0 so y = -10, so y-intercept : (0, -10))
x-intercept when y = 0 so
x^2 + 3x − 10 = 0
(x +5)(x - 2) = 0
x + 5 = 0; x = -5
x - 2 = 0; x = 2
So x-intercepts: (-5, 0) and (2,0)