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harina [27]
2 years ago
5

Evaluate 3|-4| 2 -2 1

Mathematics
1 answer:
Romashka [77]2 years ago
3 0

Answer: 12

Step-by-step explanation: 3 times 4=12

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Will someone please help me?
elena-s [515]

Answer:

8/3

Step-by-step explanation:

5 0
3 years ago
The circle below has center P, and its radius is 6in. Given that =m∠QPR170°, find the length of the major arc QSR.
kenny6666 [7]

The length of the major arc QSR is 39.77 inches

<h3>How to find the length of the major arc QSR?</h3>

The given parameters are:

m∠QPR = 170 degree

Radius, r = 6 inches

The length of the major arc QSR is calculated as:

Arc length = (360 - Angle/360) * 2πr

Substitute the known values in the above equation

Arc length = (360 - 170/360) * 2 * 3.14 * 6

Evaluate the difference

Arc length = (190/180) * 2 * 3.14 * 6

Evaluate the product

Arc length = 39.77

Hence, the length of the major arc QSR is 39.77 inches

Read more about arc lengths at:

brainly.com/question/2005046

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7 0
1 year ago
Plz answer the question
3241004551 [841]
The answer is "A" Andrew. The expenses of that hurricane was much greater than those of hurricane Hugo, Hazel, Audrey, and David.
8 0
3 years ago
Read 2 more answers
Joe owns a stock which has probability .5 of going up. This morning, he bought a ticket in a lottery game which gives him a prob
yKpoI14uk [10]

Answer:

0.00005

Step-by-step explanation:

The probability of the stock going up and that of winning in the lottery are independent.

Hence, the probability of both = P(stock going up) × P(winning in the lottery) = 0.5 × 0.0001 = 0.00005

7 0
3 years ago
(Mathswatch)Can someone please help me with these questions. please I begg you! I BEGG YOU
s2008m [1.1K]

Answer:

y=-\frac{8}{15}x+\frac{289}{15}

Step-by-step explanation:

First of all, the equation of the circle is

x^{2} +y^{2} =17^{2}

Where the radius is 17 units long.

Now, we need to find the slope of the radius OP,

m=\frac{15}{8}

Then, we use the perpendicular rule

\frac{15}{8} \times m_{tangent}=-1\\   m_{tangent}=-\frac{8}{15}

Next, we use the point-slope formula, with the slope we found and the point (8,15).

y-y_{1} =m(x-x_{1} )\\y-15=-\frac{8}{15}(x-8) \\y=-\frac{8}{15}x+\frac{64}{15}+15\\  y=-\frac{8}{15}x+\frac{289}{15}

Therefore, the equation of the tangent line is

y=-\frac{8}{15}x+\frac{289}{15}

8 0
2 years ago
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