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asambeis [7]
3 years ago
13

What is lim x→3 x^2 - x - 6/ x - 3

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

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Answer:

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Step-by-step explanation:

-9x+1=-x+17

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Subtract 17 on both sides:

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Divide both sides by 8:

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Check x=-2!

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3 years ago
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MatroZZZ [7]

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<h3>Exponential equation</h3>

A Exponential equation is in the form:

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8 0
2 years ago
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Ksju [112]

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4 0
3 years ago
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Answer:

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2 years ago
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irina1246 [14]
Work is attached to this post

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