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3 years ago

Help with 1 and 2 please

Mathematics

1 answer:

Kipish [7]3 years ago

5 0

Cggccgchgvgubghvhgugygy

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543.2 - 3.28 help !!!!!!!!

Kitty [74]

Answer:

539.92

Step-by-step explanation:

First line up the decimals and just subtracted. And that's it.

7 0

4 years ago

Read 2 more answers

Please help me on this i will give you brainliest

stealth61 [152]

We know that the angles of a straight line equal 180 degrees and also the sum of all angles in a triangle equals 180 degrees, therefore you can determine x = 38

7 0

3 years ago

Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

3 years ago

Match the graph with its equation.

Fiesta28 [93]

It is the second choice y=-3.

The line is on the y- axis

6 0

4 years ago

Read 2 more answers

ALGEBRA 2 QUESTION URGENT HELP PLEASE!!

NARA [144]

Answer:

d. the quantity of negative twenty plus sixteen i all over forty one.

Step-by-step explanation:

We want to simplify the complex number:

$\frac{\sqrt{-16} }{(3-3i)+(1-2i)}$

We rewrite to obtain:

$\frac{\sqrt{16}\times \sqrt{-1} }{(3+1)+(-3i-2i)}$

Recall that: $\sqrt{-1}=i$ and $-1=i^2$

We simplify to get:

$\frac{4i}{4-5i}$

We rationalize to get:

$\frac{4i}{4-5i}\times\frac{4+5i}{4+5i}$

$\frac{4i(4+5i)}{(4-5i)(4+5i)}$

$\frac{16i+20i^2}{4^2+5^2}$

$\frac{16i-20}{16+25}$

$\frac{-20+16i}{41}$

The correct answer is D

8 0

4 years ago