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earnstyle [38]
3 years ago
14

Step by step how to solve -2.3x=.46

Mathematics
1 answer:
Igoryamba3 years ago
7 0

                                             <u>-2.3 x  =  0.46</u>
Step 1:
Divide each side by -2.3 :        x  =  - 0.46 / 2.3

Step 2:
To simplify the fraction,
divide -0.46 by 2.3 :                  <em>x  =  - 0.2
</em>

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What is (4x+1)(2x-1)
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At a farmers market, oranges sell for $5 per bag and apples sell for $3 per
dimulka [17.4K]

Answer:

A. 3 bags of oranges, 4 bags of apples

Step-by-step explanation:

If O is number of bags of oranges and A is number of bags of apples:

O + A = 7

5O + 3A = 27

We can solve this system of equations with either substitution or elimination.  I like to use substitution, but you can use whichever you prefer.

O = 7 − A

5 (7 − A) + 3A = 27

35 − 5A + 3A = 27

35 − 2A = 27

8 = 2A

A = 4

O = 7 − A

O = 3

Teresa bought 3 bags of oranges and 4 bags of apples.

4 0
3 years ago
What number should be added on both sides of the equation to complete the square?x^2-10x=7
ArbitrLikvidat [17]
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3 0
3 years ago
Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
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