Question

Help with my math please please Thank you! :)

Answer 1

Answer:

cosФ = $\frac{\sqrt{11} }{6}$    

Step-by-step explanation:

Given as Sin Ф = $\frac{5}{6}$

And According to Pythagorean identity ,

sin²Ф + cos²Ф = 1

I,e cos²Ф = 1 - sin²Ф

Or, cosФ = √(1 - sin²Ф )

∵ sinФ =  $\frac{5}{6}$

So , cosФ = $\sqrt{1 - (\frac{5}{6})^{2}}$

Or , cosФ =$\sqrt{( 1 - (\frac{25}{36})$

Or,  cosФ = $\sqrt{\frac{(36-25)}{36} }$

Or, cosФ = $\frac{\sqrt{11} }{6}$      Answer

Answer 2

Cos=square root of 11/ 6