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vodka [1.7K]
3 years ago
5

Which of the following areas have the highest population density?

Geography
2 answers:
ddd [48]3 years ago
5 0
The answer is United States
Romashka [77]3 years ago
4 0

New York City has the highest population density.

Answer: Option D

<u>Explanation: </u>

In United States, the city known as New York City or New York is said to be the most populated city. The population in NY is about 8,398,748 that is distributed across an area of three hundred square miles approximately.

The major city in United States that has a dense population is New York.  There are about three million residents in NY who are born outside the US.  The NY metropolitan area has been estimated to generate a Gross Metropolitan Product if US $1.9 trillion.  

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Answer:

Religion has been the custom followed by humans since the ancient times. The various religions seen in the world are Hindu, Muslims, Christian etc. each religion having their own beliefs and rituals to follow. But the same religion seems to be altered due to various reasons like, the geographic features, ancestors, government influence, evolution , technology which makes the people in one region follow the religion according to their adaptation .

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3 years ago
Local government is funded by property taxes.<br><br><br> TRUE<br> FALSE
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True.. property tax is the main source of the local government's revenue
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What is the value of X6? <br><br> Show the solution.
wariber [46]

Answer : The value of x_6 is \sqrt{7}.

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of x_1.

Using Pythagoras theorem in triangle 1 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_1)^2=(1)^2+(1)^2

x_1=\sqrt{(1)^2+(1)^2}

x_1=\sqrt{2}

Now we have to calculate the value of x_2.

Using Pythagoras theorem in triangle 2 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_2)^2=(1)^2+(X_1)^2

(x_2)^2=(1)^2+(\sqrt{2})^2

x_2=\sqrt{(1)^2+(\sqrt{2})^2}

x_2=\sqrt{3}

Now we have to calculate the value of x_3.

Using Pythagoras theorem in triangle 3 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_3)^2=(1)^2+(X_2)^2

(x_3)^2=(1)^2+(\sqrt{3})^2

x_3=\sqrt{(1)^2+(\sqrt{3})^2}

x_3=\sqrt{4}

Now we have to calculate the value of x_4.

Using Pythagoras theorem in triangle 4 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_4)^2=(1)^2+(X_3)^2

(x_4)^2=(1)^2+(\sqrt{4})^2

x_4=\sqrt{(1)^2+(\sqrt{4})^2}

x_4=\sqrt{5}

Now we have to calculate the value of x_5.

Using Pythagoras theorem in triangle 5 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_5)^2=(1)^2+(X_4)^2

(x_5)^2=(1)^2+(\sqrt{5})^2

x_5=\sqrt{(1)^2+(\sqrt{5})^2}

x_5=\sqrt{6}

Now we have to calculate the value of x_6.

Using Pythagoras theorem in triangle 6 :

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(x_6)^2=(1)^2+(X_5)^2

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x_6=\sqrt{(1)^2+(\sqrt{6})^2}

x_6=\sqrt{7}

Therefore, the value of x_6 is \sqrt{7}.

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Which of the following is a benefit created by the construction of the Aswan High Dam in Egypt? i. Generated electricity is used
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Answer:

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Explanation:

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Answer:

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