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3 years ago

10

Please help!posted picture of question

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

We have the following functions:
f (x) = 3x ^ 2-1
g (x) = x + 2
Adding both functions we have:
(f + g) (x) = f (x) + g (x)
(f + g) (x) = (3x ^ 2-1) + (x + 2)
(f + g) (x) = 3x ^ 2 + x + 1
Answer:
The answer for this case is given by:
(f + g) (x) = 3x ^ 2 + x + 1
option 3

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nika2105 [10]

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2 years ago

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steposvetlana [31]

Answer:

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Step-by-step explanation:

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2 years ago

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kari74 [83]

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2 years ago

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Gelneren [198K]

$\frac{7}{8} \times \frac{1}{2}$

$= \frac{7 \times 4}{8}$

$= \frac{28}{8}$

$= \frac{ \cancel{28}}{ \cancel{8}}$

$= \frac{14}{4}$

$= \frac{ \cancel{14}}{ \cancel{4}} = \frac{7}{2}$

<h2>The required answer is 7/2 </h2>

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3 years ago

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3 years ago