(a) 8x = 56
1 answer:
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Answer:
( , 0 )
Step-by-step explanation:
To find the x- intercepts let y = 0, that is
2x² + 3x - 2 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 2 = - 4 and sum = + 3
The factors are + 4 and - 1
Use these factors to split the x- term
2x² + 4x - x - 2 = 0 ( factor the first/second and third/fourth terms )
2x(x + 2) - 1 (x + 2) ← factor out (x + 2) from each term
(x + 2)(2x - 1) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
2x - 1 = 0 ⇒ 2x = 1 ⇒ x =
The x- intercepts are (- 2, 0 ), ( , 0 )
Answer:
Question 9
(a) The distance, Jalaj walks in one day is 4.4 km
(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8
Question 10
(b) The difference between the largest and smallest areas is 2,400 m²
Step-by-step explanation:
Question 9
(a) The distance Jalaj walks in 5 days = 22 km
Whereby Jalaj walks equal distance every day, we have;
The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day
The distance, Jalaj walks in one day = 4.4 km
(b) The amount he raises for every kilometer he walks = $1.60
The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60 = $8
Question 10
(b) The given side length of the square = 120 meters to the nearest 10 meters
Therefore;
The maximum dimension for the side length of the square = 120 + 10/2 = 125
The largest possible area of the square, = 125 m × 125 m = 15,625 m²
The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m
The smallest possible area of the square, = 115 m × 115 m = 13,225 m².
The difference between the largest and smallest areas, -
= 15,625 - 13,225 = 2,400 m².