Question

How many instructions could fit into a 256 byte memory unit, given a 32-bit architecture?

Answer 1

Answer:

64

Explanation:

We have given the 32 bit architecture

We know that 1 byte =8 bit

So memory of given architecture 32 bit $\frac{32}{8}=4bytes$

Total memory = 256 bytes

So total number of instruction that fit into 256 bytes $\frac{256}{4}=64$

So total 64 instruction can be fit in 256 byte memory.